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3 years ago

Find the selling price of a $249.50 cell phone with a 30% markup

Mathematics

1 answer:

algol [13]3 years ago

3 0

Answer:

$324.35

Step-by-step explanation:

249.50x74.80=74.85. markup=add, 74.85+249.50=324.35

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Solve f (x)=3x+6 f(300)

sveta [45]

Answer:

$f(300)=906$

Step-by-step explanation:

$f(x)=3x+6\\\\f(300)=3(300)+6\\\\f(300)=900+6\\\\\boxed{f(300)=906}$

Hope this helps.

8 0

3 years ago

Factor 64v^3 + 192v^2 -56v - 168

Kaylis [27]

Hello from MrBillDoesMath!

Answer:

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )

Discussion:

Given

64v^3 + 192v^2 - 56 v - 168

Factor 64v^2 from the first two terms. Factor 56 from the last two terms:

64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms

(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()

8(v+3)(8v^2-7) => factor 8y^2-7

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )

Thank you,

MrB

4 0

3 years ago

10 is 8% of a, and 5 is 4% of b. c equals b/a. What is the value of c?? step by step explanation pls...

klio [65]

Answer:

c = 1

Step-by-step explanation:

"10 is 8% of a": 0.08a = 10, or a = (10/0.08)

"5 is 4% of b": 0.04b = 5, or b = (5/0.04)

"c equals b/a": c = (b/a)

----

What is the value of c?

c = (b/a)

c = ((5/0.04)/(10/0.08))

c = (5/0.04)*(0.08/10)

c = (5/10)*(0.08/0.04)

c = (1/2)*(2)

c = 1

5 0

2 years ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

Part a: The height of the ball when t = 2 seconds:

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

Part b: The height of the ball when t = 4 seconds:

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$