Answer:
Discontinuity at (-4,-2), zero at (-2,0).
Step-by-step explanation:
We are given that a function 

We have to find the discontinuity and zero of the given function.
Discontinuity: It is that point where the function is not defined.
It makes the function infinite.


When x=-4 then 
 It is indeterminate form
 It is indeterminate form 
Function is not defined 
After cancel out x+4 in numerator and denominator  then we get 

Substitute x=-4

Therefore, the point of discontinuity is (-4,-2).
Zero: The zero of the function is that number when substitute it in the given function then the function becomes zero.
When substitute x=-2
Then , 
The function is zero at (-2,0).
Hence, option C is true.
 
        
             
        
        
        
G(x)=-(x^2-6x+5)
      =-(x-6x+9-9+5)
      =-(x-3)²+4
It is reflected across the a axis, shifted 3 units to the right, shifted 4 units up, and It has an axis of symmetry at x=3
        
                    
             
        
        
        
<span><span>x=<span><span><span>20</span></span><span><span><span>(y−3)</span><span><span>2</span><span></span></span></span></span><span></span></span>−1</span><span>
</span></span>
        
             
        
        
        
If Sachiko lets x represent the length of the side of the square and she wants to find the length of the perimeter of the square, it is appropriate for her to ...
... B. Set the area equal to x², solve for x, and then multiply the value of x by 4.
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The area of a square of side length x is x·x = x². The perimeter of a square of side length x is x+x+x+x = 4·x.