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3 years ago

Graph the equation x+4y=12 by plotting points.

Mathematics

1 answer:

Kaylis [27]3 years ago

4 0

Answer:

slope=-1/4 y intercept=(0,3)

Step-by-step explanation:

(0,3)

(12,0)

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Liquid Tylenol has 325 milligrams of acetaminophen per 12.5 milliliters of liquid medicine (a fact that would be commonly abbrev

gulaghasi [49]

Answer:

10 milliliters

Step-by-step explanation:

260 mg/ 325 mg = x ml / 12.5 ml

12.5 ml x (260 mg / 325 mg) = 10 ml

7 0

3 years ago

C=-7/15 and x=2/5 c-4x write your answer in simplest form

pogonyaev

9514 1404 393

Answer:

-31/15

Step-by-step explanation:

Put the numbers in the expression and do the arithmetic.

$c-4x=-\dfrac{7}{15}-4\cdot\dfrac{2}{5}=-\left(\dfrac{7}{15}+\dfrac{8}{5}\right)\\\\=-\left(\dfrac{7}{15}+\dfrac{24}{15}\right)=\boxed{-\dfrac{31}{15}}$

Your graphing calculator can probably help with this.

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3 years ago

A cable installer charges $40.00 per hour plus a $60.00 service charge. Your father's firm hires him to hook up his company's in

balandron [24]

Set up the equation ... 60 + 40X = total charges... where X is the number of hours (8.5)

60 + 40(8.5) = ?
60 + 340 = ?
400 = total charges

7 0

3 years ago

Read 2 more answers

How many significant figures in 0.003010

Tamiku [17]

4 significant figures.
we can start counting the numbers after all the zeros in front. the zeros in front doesn't count in. but the zeros after the first number that is 1 or larger counts.
therefore we only need to look at 3010

4 0

3 years ago

Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.

SSSSS [86.1K]

Answer:

$\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}$

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

$-x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}$

6 0

3 years ago