Answer:
Step-by-step explanation:
For the y to cancel out, you would have to divide y by 5. Whenever you do one thing to a side, you <u><em>have</em></u> to do the same on the other side. Once you do so, you'll get : 
<em>Hope this helps!!</em>
Simplifying
x + 6 = 3x + -14
Reorder the terms:
6 + x = 3x + -14
Reorder the terms:
6 + x = -14 + 3x
Solving
6 + x = -14 + 3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3x' to each side of the equation.
6 + x + -3x = -14 + 3x + -3x
Combine like terms: x + -3x = -2x
6 + -2x = -14 + 3x + -3x
Combine like terms: 3x + -3x = 0
6 + -2x = -14 + 0
6 + -2x = -14
Add '-6' to each side of the equation.
6 + -6 + -2x = -14 + -6
Combine like terms: 6 + -6 = 0
0 + -2x = -14 + -6
-2x = -14 + -6
Combine like terms: -14 + -6 = -20
-2x = -20
Divide each side by '-2'.
x = 10
Simplifying
x = 10
Answer:
One
Step-by-step explanation:
Clearly, one triangle can be constructed as the angles 45 and 90 do not exceed 180 degrees. (so "None" is not correct)
To show that only one such triangle exists, you can apply the Angle-Side-Angle theorem for congruence.
Since one triangle can be constructed, it remains to be shown that no additional triangle that is not congruent to the first one can be created: I will use proof by contradiction. Let a triangle ABC be constructed with two angles 45 and 90 degree and one included side of length 1 inch. Suppose, I now construct a second triangle that is different from the first one but still has the same two angles and included side. By applying the ASA theorem which states that two triangles with same two angles and one side included are congruent, I must conclude that my triangle is congruent to the first one. This is a contradiction, hence my original claim could not have been true. Therefore, there is no way to construct any additional triangle that would not be congruent with the first one, and only one such triangle exists.
Answer:
13 is Prime
Step-by-step explanation:
