Question

Using and spectrophotometer, you measure 2 dilutions of NADH, and get absorbance values of 0.4 for sample A, and 0.2 for sample B. You know that the path length is 1 cm, and the extinction coefficient for NADH is 6220 (L Morcm). Using the Lambert-Beer Law equation (below), calculate the concentrations of sample A Select] and Sample B (Select ] A = log10 () = Ecl Where: A- Absorbance C- Concentration (mol 1 - Path length (cm) E = molar decadic extinction coefficient L mol. cm 1o - Intensity of the incident light 1 - Intensity of the transmitted Night

Answer 1

Answer:

The answer is "The concentration sample A= 0.00006$\frac{mol}{L}$ and concentration of sample B is 0.00003$\frac{mol}{L}$".  

Explanation:

Length of path $(l)=1 \ cm$

Coefficient extinction$(\varepsilon )=6220\ \frac{L}{Mol \ cm}$

Absorbace of sample $(A)=0.4$

Absorbace of sample $(B)=0.2$

For sample A:

$A=\varepsilon cl\\\\0.4=6220 \times c \times 1\\\\c=\frac{0.4}{6220}$

   $=0.00064\ \frac{mol}{L}$

For sample B:

$A=\varepsilon cl\\\\0.2=6220 \times c \times 1\\\\c=\frac{0.2}{6220}$

   $=0.00003\ \frac{mol}{L}$