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UNO [17]
3 years ago
13

HELPPP ME PLEASE I REALLY NEED HELP

Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0
<h3>Answer:   choice F) 12 & 1/2 square yards.</h3>

=====================================================

We'll use this formula

a & b/c = (a*c + b)/c

to convert from a mixed number to an improper fraction.

Let's convert the first mixed number to an improper fraction

a & b/c = (a*c + b)/c

3 & 3/4 = (3*4 + 3)/4

3 & 3/4 = 15/4

Repeat the same idea for the second mixed number as well

a & b/c = (a*c + b)/c

3 & 1/3 = (3*3 + 1)/3

3 & 1/3 = 10/3

--------------------

In short we have

  • 3 & 3/4 = 15/4
  • 3 & 1/3 = 10/3

Doing these conversions is useful to be able to multiply the values like so:

(15/4)*(10/3) = (15*10)/(4*3) = 150/12 = (6*25)/(6*2) = 25/2

Now use your calculator to find that 25/2 = 12.5

We can then say....

12.5 = 12 + 0.5 = 12 + (1/2) = 12 & 1/2

The answer is choice F) 12 & 1/2 square yards.

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8 0
3 years ago
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Graph the equation using the slope and the y intercept 2x-3y=8
sammy [17]

Step-by-step explanation:

<h2>Find slope-intercept structure </h2>
  • y=
  • \frac{2}{3} x -  \frac{8}{3}
  • m=2/3, b=-8/3
  • therefore the slope will be 2/3

To find y-intercept

  • let x=0
  • 2(0)-3y=8
  • -3y=8
  • y=-3/8

To find x-intercept

  • let y=0
  • 2x-3(0)=8
  • 2x=8
  • x=4

7 0
2 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
DaniilM [7]
<span>A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
The area of the circle will be found as follows:
the fraction of the sector=15/360=1/24
the area of the circle will be:
area=(fraction of the circle)/(fraction of the sector)*(area of the sector)
=1/(1/24)</span>×11.9
=285.6 m²
5 0
3 years ago
A car leaving a stop sign accelerates...what is the average speed of the car, in feet per second, equation d=1.1t^2 average spee
spayn [35]

Answer:

10.27 feet/sec.

Step-by-step explanation:

The distance traveled by the car, d in feet, is given by the function d = 1.1t^{2} .......... (1), where t is the time in seconds.

So, at t= 2 sec, from equation (1) we get d = 1.1 × 4 = 4.4 feet.

Again, at t = 5 sec, we get d = 1.1 × 32 = 35.2 feet.

Now, average speed of the car from t = 2 sec. to t = 5 sec. will be give by

\frac{\textrm {Total distance traveled}}{\textrm {Total time spent}}

= \frac{35.2 - 4.4}{5 - 2} = 10.27 feet/sec. (Answer)

8 0
3 years ago
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