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wlad13 [49]
3 years ago
15

HI CAN ANYONE PLS ANSWER DIS MATH PROBLEM!!!!!!!!!!!

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:

i believe that the answer is ç

White raven [17]3 years ago
3 0
I believe the answer is C
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-y varies inversely with x. When y = 9.6, x = 12. What is the value of k, the constant of inverse variation?
alisha [4.7K]

Question 1:

For this case we have an equation of the form:

y = \frac {k} {x}

Where,

  • <em>k: inverse variation constant. </em>

Then, substituting values we have:

y =\frac {k} {x}

From here, we clear the value of k.

We have then:

k = 9.6 * 12\\k = 115.2

Answer:

the constant of inverse variation is:

k = 115.2

Question 2:

For this case we have:

y = \frac {k} {x}

Where,

  • <em>k: constant of variation. </em>

Then, substituting the value of the constant we have:

y =\frac {5.6} {x}

We now substitute the value of x:

y = \frac {5.6} {4}\\y = 1.4

Answer:

 the value of y when x = 4 is: y = 1.4

6 0
3 years ago
Jillian is trying to save water, so she reduces the size of her square grass lawn by 8 feet on each side. the area of the smalle
tatiyna
(x - 8)^2 = 144
take the sq rt of both sides
x - 8 = 12
x = 12 + 8
x = 20

20 feet by 20 feet
7 0
3 years ago
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Please answer this correctly
kirill [66]

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3 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
STatiana [176]

Answer:

24761 mosquitoes

5.4 days

Step-by-step explanation:

Let the equation that shows the population of the mosquitoes after x days,

A=P(1+r)^x

Where,

P = Initial population,

r = rate of increasing per day,

Here, A = 1000, when x = 0,

1000=P(1+r)^0\implies P = 1000

A = 1900 when x = 1,

1900 = P(1+r)^1\implies 1900 = 1000(1+r)\implies 1.9 = 1 + r\implies r = 0.9

Thus, the required function that represents the population after x days,

A=1900(1+0.9)^x=1900(1.9)^x

If x = 4,

The number of mosquito after 4 days,

A=1900(1.9)^4 = 24760.99\approx 24761

If A = 60,000,

60000 = 1900(1.9)^x

\frac{600}{19}=1.9^x

Taking log both sides,

\log(\frac{600}{19})=x\log 1.9

\implies x = \frac{\log(\frac{600}{19})}{\log 1.9}=5.378\approx 5.4

Thus, there will 60,000 mosquitoes after 5 days.

6 0
3 years ago
in a survey students were asked to votefortheir favorite color. they had 5 colors to choosefrom. eachof the colors received 8 vo
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5 colors x 8 votes = 40 students
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