At noon, the temperature was 36 degrees. At midnight, the temperature was 30 degrees. By 6:00 am it drooped 5 degrees. Since it dropped 5 degrees, you subtract 5 from 30, which equals 25. It then increased by 11 degrees. Since the temperature increased, you add 11 to 25, which equals 36. At noon, the temperature was 36 degrees.
2x - 5y = 11. (4, a). x = 4, y = a
Substituting into 2x - 5y = 11
2(4) - 5(a) = 11
8 - 5a = 11
-5a = 11 - 8
-5a = 3
a = 3/-5 = -3/5 =- 0.6
Other coordinate = -3/5 = -0.6
For the function 1,
To find the equation for this function, first you take any two points and from these points you will find the slope of line and then put it in the equation of line.
(x₁,y₁)=(0,4)
(x₂,y₂)=(1,7)
slope=m=y₂-y₁/x₂-x₁
=7-4/1-0
=3/1
=3
Equation of a line
f(x)=mx+c
where m is the slope and c is the y intercept.
f(x)=3x+4
For the function 2,
As you have given the equation of a function which is
f(x)=-2x+3
you can easily fill the table,
I do it for one value for other values you will do the same procedure.
For x=-2
f(x)=-2(-2)+3
= 7
x f(x)
-----------------
-2 7
-1 5
0 3
1 1
2 -1
For the Function 3,
You can get the values from the graph directly but you can also solve it by finding the equation first and then by putting method you get the value.
Equation of a line
f(x)=mx+c
where m is the slope and c is the y intercept.
m=(y₂-y₁)/(x₂-x₁)
(x₁,y₁)=(0,-3)
(x₂,y₂)=(6,0)
m=(0-(-3))/(6-0)
m=1/2
f(x)=1/2x-3
x f(x)
-----------------
-2 -4
-1 -7/2
0 -3
1 -5/2
2 -2
The graph of function 1 and 2 are attached below.
Answer:
x = 5
angle measure labelled 6x is 30degrees
Step-by-step explanation:
Find the diagram attached
from the diagram;
6x = 30 (vertically opposite angle)
Divide both sides by 6
6x/6 = 30/6
x = 5
Get the angle labelled 6x
6x = 6(5)
6x = 30degrees