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3 years ago

Please help to solve this

Mathematics

1 answer:

Goryan [66]3 years ago

6 0

Answer:

☥ $\underline{ \underline{ \red{\large{\tt{S \: O \: L \: U \: T \: I \: O \: N}}}}} :$

Let Cost Price ( CP ) be x

☃ $\large{ \tt{MP = x + 30\% \: of \: x}}$

➝ $\large{ \tt{x + \frac{30}{100}x }}$

➝ $\large{ \tt{x + 0.3x }}$

➝ $\large{ \tt{1.3x}}$

☂ $\large{ \tt{SP = 1.3x - 15\% \: of \: 1.3x}}$

⇾ $\large{ \tt{1.3x - \frac{15}{100} \times 1.3x}}$

⇾ $\large{ \tt{1.3x - 0.195x}}$

⇾ $\large{ \tt{1.105x}}$

☼ $\large{ \tt{Profit = SP - CP}}$

⟶ $\large{ \tt{1.105x - x}}$

⟶ $\large{ \tt{0.105x}}$

♨ $\large{ \tt{P\% = \frac{Profit}{CP} \times 100 \%}}$

⤑ $\large{ \tt{ \frac{0.105x}{x} \times 100\%}}$

⤑ $\boxed{ \large{ \purple{\tt{10.5\%}}}}$

Hence , Profit % = 10.5 %

♕ Hope I helped ! ♡

☄ Have a wonderful day / night ! ♫

✎ $\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}$

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

40+88+15=128+15=143

There are three rectangles that compose this shape. The first one has side lengths of 5 & 8 (l times w=a 5 times 8=40, area of the rectangle is 40). The second one has side lengths of 8&11 (8 times 11=88, area is 88). Final rectangles has side lengths of 16-(8+5) and 5 (16-13=3, 3 times 5=15, Area=15). All three of those rectangles added up is 143 as an area of the figure.

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2 years ago

3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are

natta225 [31]

Using the binomial distribution, the probabilities are given as follows:

a) 0.4159 = 41.59%.

b) 0.5610 = 56.10%.

c) 0.8549 = 85.49%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

n = 3, p = 0.76.

Item a:

The probability is P(X = 2), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159$

Item b:

The probability is P(X < 3), hence:

P(X < 3) = 1 - P(X = 3)

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390$

Then:

P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.

Item c:

The probability is:

$P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549$

More can be learned about the binomial distribution at brainly.com/question/24863377

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Please help to solve this ​

Please help to solve this