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3 years ago

How much voltage is required to run 1.6 A of current through a 240 0 resistor?

Mathematics

2 answers:

vichka [17]3 years ago

8 0

Here, current (I) = 1.6A

resistance(R) = 240 ohm

we know, voltage(v) =I×R

=1.6×240

=384 VOLTS

Hope i am clear and correct

Zepler [3.9K]3 years ago

8 0

Answer:

380 V

Step-by-step explanation:

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Find the length of LM if L is the midpoint of NM. NL = 3x + 1, LM = 8x - 24.

SashulF [63]

Answer:

LM = 16

Step-by-step explanation:

From the question given:

L is the midpoint of NM

NL = 3x + 1

LM = 8x - 24

LM =?

Next, we shall determine the value of x.

This can be obtained as follow:

Since L is the midpoint of NM, it means that NL and LM are equal i.e

NL = LM

Thus, we can obtain the value of x as follow:

NL = 3x + 1

LM = 8x - 24

NL = LM

3x + 1 = 8x - 24

Collect like terms

3x - 8x = - 24 - 1

-5x = - 25

Divide both side by - 5

x = -25/-5

x = 5

Finally, we shall determine the length of LM as follow:

LM = 8x - 24

x = 5

LM = 8(5) - 24

LM = 40 - 24

LM = 16

Therefore, the length of LM is 16

8 0

3 years ago

E = MV^2 ÷ 2 + mgh, Make V Subject of the formula

Stels [109]

Answer:

$\red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}$

Step-by-step explanation:

$E = MV^2 ÷ 2 + mgh \\ \\ E - mgh = MV^2 ÷ 2 \\ \\ 2(E - mgh)= MV^2 \\ \\ \frac{2(E - mgh)}{M}=V^2 \\ \\ \sqrt{\frac{2(E - mgh)}{M}} = V \\ \\ \red{ \bold{ V = \sqrt{\frac{2(E - mgh)}{M}}}}$

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3 years ago

20 point REWARD + Brainleist <3

jek_recluse [69]

B the answer is b because yiu do like add e square 27 +* 9 + x = 8 -/273/73

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2 years ago

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Butoxors [25]

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Step-by-step explanation:

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Andrews [41]

Answer:

-5 and -5.

Step-by-step explanation:

Two negative numbers multiply to make a positive and add to make a negative.

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2 years ago