The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.
Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that
L = 2W - 5
Substituting L into P, we have
P = 2(2W - 5 + W)
P = 2(W - 5)
Since P = 56, we have
2(W - 5) = 56
~Dividing both sides by 2, we have
W - 5 = 56/2
W - 5 = 23
Adding 5 to both sides, we have
W = 23 + 5
W = 28 inches
Substituting W into L, we have
L = 2W - 5
L = 2(28) - 5
L = 56 - 5
L = 51 inches
So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Learn more about perimeter of a rectangle here:
brainly.com/question/16715918
Answer:
B. 6.2
Step-by-step explanation:
The calculation is done by hand and verified by a TI-84 calculator.
Answer:
72,000,000
Step-by-step explanation:
36x2,000,000= 72,000,000
Using the given information, the value of Σfd is 800
<h3>Calculating mean using Assumed mean </h3>
From the question, we are to determine the value of Σfd
The formula for mean, using the assumed mean method is given by
Where 
is the mean
A is the assumed mean
From the given information,
Putting the parameters into the equation, we get
Hence, the value of Σfd is 800
Learn more on Mean here: brainly.com/question/20118982
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