Answer:
3(4) + 5
Step-by-step explanation:
Use BIDMAS (Brackets, indicies, division, multiplication, addition, subtraction.)
Answer:
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Step-by-step explanation:
A multiple of a number is obtained after multiplying the number by an integer.
Here,
x, y are any two integers greater than 1,
(1) We have,


∵ y is an integer ⇒ 3y + 7 is also an integer,
⇒ y × an integer = x
That is, when we multiply y by a number we obtain x,
∴ x is a multiple of y.
Thus, statement (1) ALONE is sufficient.
(2),

I.e.
, where a is an integer,

∵ x and x - 1 are disjoint numbers,
There are three possible cases,
Case 1 : x is multiple of y
Case 2 : (x-1) is a multiple of y,
Case 3 : neither x nor x - 1 are multiple of y but their product is multiple of y,
Thus, statement (2) is not sufficient.
Answer:
The correct answer is "1668". A further solution is provided below.
Step-by-step explanation:
According to the question,
Estimated proportion,


Margin of error,
E = 0.02
Level of confidence,
= 90%
= 0.90
Critical value,
Now,
⇒ 



or,
Answer: k = {8, -8}
<u>Step-by-step explanation:</u>
In order for a quadratic equation to have exactly one solution, the discriminant must equal zero. → b² - 4ac = 0
4x² + kx + 4 = 0
↓ ↓ ↓
a=4 b=k c=4
b² - 4ac = 0
k² - 4(4)(4) = 0
k² = 64
k = √64
k = ± 8
Write out the numbers between 24 and 33: {24, 25, 26, 27, 28, 29, 30, 31, 32, 33}
How many numbers have we here? 10.
How many of these numbers are odd? {25, 27, 29, 31, 33}
Strictly speaking, "between 24 and 33" does not include {24, 33}.
Thus, the odd numbers between 24 and 33 are {25, 27, 29, 31}
The chances of drawing an odd number between 24 and 33 are then 4 / 10.
If, however, we omit the endpoints 24 and 33, then there are 8 numbers between 24 and 33: {25, 27, 29, 31}
and the odds of choosing an odd number from these eight numbers is 4/8, or 1/2, or 0.50.