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ludmilkaskok [199]
2 years ago
14

PLEASE HELP ME WITH THIS QUESTION!!! WHATS THE ANSWER?? I WILL GIVE YOU BRAINLIEST AND A THANKS!!! THANK YOUUU!!! <33

Mathematics
2 answers:
Free_Kalibri [48]2 years ago
6 0

Answer:

A) 113 m²

Step-by-step explanation:

Use the formula for area of a circle.

Area of a circle = πr²

π = pi = 3.14 (rounded)

r = radius

² = the power of 2, or the radius (in this case) multiplied by itself.

Note that the radius is given, and it is 6. Plug in 6 for the radius:

A (circle) = π(6)²

First, solve the power. Multiply 6²:

6² = 6 * 6 = 36

Next, multiply 36 with π (3.14):

36 x 3.14 = 113.04

A) 113 m² is your closest answer.

~

Basile [38]2 years ago
3 0
<h2><u>Solution</u>:-</h2>

Radius (r) of a circle = 6 m.

\bigstar To Find the area of the circle.

Since we know,

• Taking value of π = 3.14

\dag Area of a circle is πr².

So, Area of the circle = 3.14 × (6)²

Area of the circle = 3.14 × 6 × 6

Area of the circle = 113.04 = 113 m².

The area of the circle is <u>1</u><u>1</u><u>3</u><u> </u><u>m²</u>.

Hence, option (A) <u>1</u><u>1</u><u>3</u><u> </u><u>m²</u> is correct. [Answer]

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Mnenie [13.5K]

Answer:

Area of shaded part ABCEF = 66 sq.cm

Step-by-step explanation:

AB = 8cm

CD = 8cm

Let DE = x cm

CE = 3x cm

CD =  CE + DE = 8cm

        x + 3x = 8

4x = 8

x = 8/4 = 2 cm

DE = 2cm

CE = 3 * 2 = 6 cm

Area of triangle ADE = 1/2 * base * height

                                   = 1/2 * DE * AD

                                    = 1/2 * 2 * 11 = 11 sq. cm

Area of triangle AEF = Area of triangle ADE = 11 sq. cm

Area of Rectangle ABCD =  l * b = 8 * 11 = 88 sq.cm

Area of shaded part ABCEF =  Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)

    = 88 - ( 11 + 11 )  = 88 -22 = 66 sq.cm

6 0
3 years ago
Pls help I’ll brainlest due ASAP
Sholpan [36]
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3 0
3 years ago
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For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
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3 years ago
Lauren describes a parabola where the focus has a positive, nonzero x coordinate. Which parabola(s) could Lauren be describing?
sdas [7]

it answer is c ,d and f

5 0
3 years ago
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you work from 7:00 am to 11:00 am and from 12:00pm to 4:00 pm. your hourly rate is $7.50. You do not work overtime. Find the hou
Viktor [21]

Answer:

Worked 40 hrs in week

Pay $300 for week

Step-by-step explanation:

Hours: 7-11a.m = 4

12-4p.m = 4 So, 4+4=8 hrs per day

So, 8 hrs per day × 5 days a week (8×5)=40

Worked 40 hrs in week

Pay: $7.50/hr So, $7.50×40 hrs (7.50×40)=300

So, $300 pay for week

7 0
3 years ago
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