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Ivahew [28]
3 years ago
15

Help please this is due by 11:45 also its 6th grade math btw

Mathematics
2 answers:
xeze [42]3 years ago
7 0

Answer: 578 m2

Step-by-step explanation: Hope this helps!! <3

Serga [27]3 years ago
6 0

Answer:

578m^{2}

Step-by-step explanation:

You might be interested in
Help please............
Arisa [49]
The answer is D I think, cause sum means plus and product means times
7 0
3 years ago
Read 2 more answers
0.66666667 as a fraction
Ierofanga [76]

Answer:

__________________________________________

    The correct answer is:   " \frac{2}{3} " .

__________________________________________

Note:  Let's assume that this given decimal value  is really:

"0.66666666666666666....."  ;

(non-terminating; but repeating the singing digit, "7" ; yet rounded to:

" 0.66666667 " ;  

then:  " 0.666... "    = \frac{666}{999}  ;

                             

                               =  (666 ÷ 111) / (999 ÷ 111)  ;

                               =  6/9 ;

                              = (6÷3)/(9÷3)  ;

                               =   2/3 ;

                             

                               =   " \frac{2}{3} "

 

                              →  which is our answer.

____________________________________________

 Or:   " 0.6666... "  =  666 ÷ 999 = ?  ;

                        using calculator :

                               =  0.66666667 ;  

        →  which is the "rounded off" number of "0.6666..." ;

                                                                — (infinitely repeating) ;

                  →   So 666 ÷ 999 =

                  →   "  \frac{666}{999} " ;

               

                               =  " \frac{2}{3} " ;  

                               →  Either use a "fraction calculator" ;

       or simplify as aforementioned.    

____________________________________________

Hope this answer is helpful to you!

       Best wishes to you in your academic pursuits

              — and within the "Brainly" community!

____________________________________________

7 0
3 years ago
Read 2 more answers
(Re-Asking This Question, NO scam answers or LINKS. I will report.)
AlexFokin [52]

Answer:

Yes

Step-by-step explanation:

This is because the first point in the parenthesis is x and the second is y. If we know this, we can substitute -5 in for x and -6 in for y to get that -15 - (-12) > -4. When you subtract by a negative number, it is the same as adding by that number, so -15 - (-12) = -15 + 12, so we get that -3 > -4. This is true because when you have negative numbers, the lesser negative number is the greater one (Ex. -5 > -6).

3 0
3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
Simplify 7 - 2(5 - 2x) -10x + 25 -4x - 3
Kisachek [45]

Hi,

Let's simplify this equation step-by-step.

7−2(5−2x)−10x+25−4x−3

Distribute:

=7+(−2)(5)+(−2)(−2x)+−10x+25+−4x+−3

=7+−10+4x+−10x+25+−4x+−3

Combine Like Terms:

=7+−10+4x+−10x+25+−4x+−3

=(4x+−10x+−4x)+(7+−10+25+−3)

=−10x+19

Answer:

=−10x+19

Have a great day!

8 0
4 years ago
Read 2 more answers
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