Answer:
UCL (x bar) = 424
LCL (x bar) = 376
Step-by-step explanation:
Given:
Average calories contained, μ = 400
Standard deviation, σ = 30 calories
Sample size, n = 25
a) UCL (x bar) =
On substituting the respective values, we get
UCL (x bar) = ![400+\frac{4\times30}{\sqrt{25}}](https://tex.z-dn.net/?f=400%2B%5Cfrac%7B4%5Ctimes30%7D%7B%5Csqrt%7B25%7D%7D)
or
UCL (x bar) = 424
Similarly,
LCL (x bar) =
On substituting the respective values, we get
LCL (x bar) = ![400-\frac{4\times30}{\sqrt{25}}](https://tex.z-dn.net/?f=400-%5Cfrac%7B4%5Ctimes30%7D%7B%5Csqrt%7B25%7D%7D)
or
LCL (x bar) = 376
The answer would be C because 24-3=21 then you would do 21/1.50=14
Answer:
See example below.
Step-by-step explanation:
To scale down by a factor of 1/10, multiply the side length or distance by 1/10.
Example:
If the distance was 5 then 5*1/10 = 5/10 = 1/2 is the scaled down version.
Answer:
C) 16, 6
Step-by-step explanation:
- Set AB and DC equal to eachother. 4x = x + 12.
- Subtract x from both sides. 3x = 12
- Divide by 3 to get x alone. x = 4
- Plug this x value in the equation for AB. 4•(4) = 16
- We know the AD equals 6, so that will be one of the values and we now know that AB equals 16.