The equation of the line in point-slope form is: C. y − 5 = −(x − 2).
<h3>What is the Point-Slope Equation of a Line?</h3>
A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).
Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:
Slope (m) = rise/run = 3 units/3 units = 1
Negative reciprocal of 1 is -1.
The slope of the line would be m = -1.
Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:
y - 5 = -1(x - 2)
y − 5 = −(x − 2)
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Answer:
1/4 or decimal : 0.25.
Step-by-step explanation:
I'm pretty sure this is right
As shown in the given figure
line a // line b ⇒ given
MR and NP are transversals
So, for ΔMOP and ΔRON , we can conclude the following
(1) ∠1 = ∠2 ⇒⇒⇒ alternative angles are congruent
(2) ∠ MOP = ∠ RON ⇒⇒⇒ vertical angles are congruent
(3) ∠ 4 = ∠ 3 ⇒⇒⇒ alternative angles are congruent
So, from 1,2 and 3
∴ ΔMOP <span>~ </span>ΔRON by AAA-Rule
Answer:
{-1,0,1}
Step-by-step explanation:
The domain of a function is the set of all input values. The input values are the first coordinate in any coordinate pair (x,y).
So the domain here is {-1, 0, 1}.
x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616
<u>Explanation:</u>
We know
(x+y)ⁿ = ∑ ⁿCₐxⁿ⁻ᵃyᵃ
and ⁿCₐ = n! / ( a! ) . ( n-a )!
So,
(x+6)⁸ = ⁸C₀x⁸ + ⁸C₁(x)⁸⁻¹(6)¹ + ⁸C₂(x)⁸⁻²(6)² + ⁸C₃(x)⁸⁻³(6)³ + .......+ ⁸C₈(x)⁸⁻⁸(6)⁸
= ₓ⁸ + 8x⁷ₓ 6 + 28x⁶ₓ 36 + 56x⁵ₓ 216 + 70x⁴ₓ 1296 + 56x³ₓ 7776 + 28x²ₓ 46656 + 8x . 279936 + 1679616
= x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616
Thus, the expansion of ( x+6)⁸ using binomial theorm is
x⁸ + 48x⁷ + 1008x⁶ + 12096x⁵ + 90720x⁴ + 435456x³ + 1306368x² + 2239488x + 1679616
