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HACTEHA [7]
3 years ago
13

Bro I need help plzzz

Mathematics
1 answer:
Allushta [10]3 years ago
6 0
48.4 hope you get it correct!
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Can anyone help with this?
Karo-lina-s [1.5K]
The answer is B. If you take the even root of a positive number, you'll get two solutions, a positive and a negative
4 0
3 years ago
Solve for x I don't know how to solve it​
mixer [17]

Answer:

x=-12

Step-by-step explanation:

32+2x=6+x+14

2x-x=6+14-32

x=-12

ST=6

TU=-12+14=2

SU=6+2=8

8 0
3 years ago
During the soccer season, Sheka scored 4 goals. Dylan scored 8 times as many goals as Sheka.
horrorfan [7]

Answer:

it's B

Step-by-step explanation:

the text gives you clues "times" is a form of multiplication. therefore it would be 8 TIMES 4

5 0
2 years ago
Read 2 more answers
What is the area of triangle UVW
kogti [31]

This is a polygon with vertices on the lattice.  Let's use Pick's Theorem,

A = (1/2) B + I - 1

where A is the area, B is the number of lattice points on the boundary and I is the number of lattice points in the interior.

In addition to the 3 vertices there are 3 more boundary points on UV and 6 more on WV, none on UV, B=3+3+6=12.   In the interior I count I=9 lattice points.

A = (1/2) 12 + 9 - 1 = 14

Answer: 14

Obviously they just want us to say this is a right triangle, so the legs are altitude and base,

A = (1/2) b h (1/2) |UW| |WV| = (1/2) (4) (7) = 14

That checks.

7 0
3 years ago
Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t
gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0
2 years ago
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