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jarptica [38.1K]
3 years ago
12

Nora bought a car last year so that she could drive to work after school. She spent $250 last year for gas. This year she spent

$295. Disregarding other factors, what is the inflation rate? 18% 19% 20% 21%
Mathematics
1 answer:
frosja888 [35]3 years ago
6 0

Answer:

here,

money spent in 1st year =$250

money spent in 2nd year=$295

total inflated amount=$295- $250

=$45

Then,

inflation rate= ($45/ $250)×100%

=18%

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Vladimir79 [104]
<h2>true</h2>

I did it on my calculater and the answer came as 13

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5 0
3 years ago
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A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
What is equation for the line that is perpendicular to y-3=-4(x+2) and passes through the point (-5,7)
jekas [21]

Answer:

y-7=1/4(x+5)

Step-by-step explanation:

y-3=-4(x+2)

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y-y1=m(x-x1)

y-7=m(x-(-5))

y-7=m(x+5)

perpendicular means negative reciprocal of the slope,

so the slope will be 1/4

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What does the graph tell you about the value of a in this function f(x)=a(x+k)^1/n+c
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For the function F defined by F(x) = x2 – 2x + 4, find F(b+3).
Ivanshal [37]

Answer:

\displaystyle F(b + 3) = b^2 + 4b + 7

Step-by-step explanation:

We are given the function:

\displaystlye F(x) = x^2 - 2x + 4

And we want to find F(<em>b</em> + 3).

We can substitute:

\displaystyle F(b + 3) = (b + 3)^2 - 2(b+3) + 4

Expand:

\displaystyle = (b^2 + 6b + 9) + (-2b -6) + 4

Rearrange:

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Combine like terms. Hence:

\displaystyle = b^2 +4b + 7

In conclusion:

\displaystyle F(b + 3) = b^2 + 4b + 7

6 0
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