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gregori [183]
3 years ago
9

A ceiling fan manufacturer claims that 89% of homes in the South have ceiling fans. A random sample of 100 Southern homes was su

rveyed, and 85 had ceiling fans. Let p hat = the proportion of the sample homes that have ceiling fans.
The probability that 85% or fewer homes in the South have ceiling fans is 0.098. Does this result provide convincing evidence against the manufacturer’s claim?

Options:

Yes, it is expected that at least 85 homes have ceiling fans.
Yes, the probability of seeing the sample result is so far from what is expected that the probability of it occurring by chance alone is very unlikely.
No, the difference between the sample result and what is expected is not extreme enough.
No, there is a very small chance of seeing the sample result. It is unlikely to occur by chance alone.
Mathematics
2 answers:
OLga [1]3 years ago
8 0

Answer:

No, the difference between the sample result and what is expected is not extreme enough.

Step-by-step explanation:

See attached picture

Semmy [17]3 years ago
6 0

The answer is

C.No, the difference between the sample result and what is expected is not extreme enough.

Also can I get brainliest please

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Answer:

$1.5

Step-by-step explanation:

Lets us first calculate energy consumed by TV in 30 days.

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Energy consumed by TV in 30 day = energy consumer by TV in a day * 30

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Convert total energy consumed in kilo watt hour  

we know that one kilowatt hour = 1000 watt-hour

Thus, 15,000 watt-hour = 15,000/1000 kilowatt-hour = 15 kilowatt-hour

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cost of electricity = 10 cents per   kilowatt-hour

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=>15*10 = 150 cents

As $1 = 100 cents

hence 150 cents = $150/100 = $1.5 .

Thus, it cost $1.5 to to operate for a month of 30 days.

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PLEASE HELP! WILL MARK BRAINLIEST!
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Answer:

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Step-by-step explanation:

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