Do y’all know the answer ?

Urgent. Factor the trinomial by grouping. Please show work. 14x^2y+9xy^2+y^3. If prime, show how you got prime answer.

ch4aika [34]

Answer:

y x (2x +y) x (7x +y)

Step-by-step explanation:

14x^2y + 9xy^2 +y^3

(Factor the expression)

y x (14x^2 +9xy +y^2)

(Rewrite the expression)

y x (14x^2 + 7xy +2xy +y^2)

(Factor the expression)

y x (7x x(2x +y) + y x (2x +y) )

(Factor the expression)

y x (2x +y) x (7x +y)

:))

3 0

3 years ago

Help for brainliest

BigorU [14]

Zeros: x = 2, x = 4

Turning point: (halfway between the zeros) x = 3, y = -1

y-intercept: where x=0, at f(0) = 8.

Axis of symmetry: the vertical line through the turning point: x = 3.

7 0

3 years ago

Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

5 0

3 years ago

Which choice most effectively combines the

shepuryov [24]

The subject-verb agreement: "Writing as" effectively combines the sentences at the underlined portion.

<h3>What is a Subject-Verb Agreement?</h3>

The grammatical principle of the subject-verb agreement states that a sentence's subject and primary verb must agree.
Particularly, singular subjects use singular verbs, whereas plural subjects use plural verbs.
There must be an agreement between the number of subjects and verbs (singular or plural).
This means that if a subject is singular, then the verb must likewise be singular, and if a subject is a plural, then the verb must also be numerous. verbs DO NOT include "an, s" in their single forms.

Therefore option (A) is the correct answer.

To learn more about Subject-Verb Agreement, refer:

brainly.com/question/1835508

#SPJ4

The underlined sentence is:

Also, studies have found that those students who major in philosophy often do better than students from other majors in both verbal reasoning and analytical <u>writing. These results</u> can be measured by standardized test scores. On the Graduate Record Examination (GRE), for example, students intending to study philosophy in graduate school have scored higher than students in all but four other majors.

7 0

2 years ago

Determine whether the given function is a solution to the given differential equation.

lesantik [10]

Given :

A function , x = 2cos t -3sin t .....equation 1.

A differential equation , x'' + x = 0 .....equation 2.

To Find :

Whether the given function is a solution to the given differential equation.

Solution :

First derivative of x :

$x'=\dfrac{d(2cos t - 3sin t)}{dt}\\\\x'=\dfrac{d(2cost)}{dt}-\dfrac{(3sint)}{dt}\\\\x'=-2sint-3cost$

Now , second derivative :

$x''=\dfrac{d(-2sint-3cost)}{dt}\\\\x''=-\dfrac{d(2sint)}{dt}-\dfrac{d(3cost)}{dt}\\\\x''=-2cost+3sint$

( Note : derivative of sin t is cos t and cos t is -sin t )

Putting value of x'' and x in equation 2 , we get :

=(-2cos t + 3sin t ) + ( 2cos t -3sin t )

= 0

So , x'' and x satisfy equation 2.

Therefore , x function is a solution of given differential equation .

Hence , this is the required solution .

8 0

3 years ago