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3 years ago

What choices are equivalent to 48/64

1 answer:

8 0

There are no choices so I’m going to assume this is simplification.

Answer:
3/4 —> this is the most simplified version of that fraction.

Explanation:
48/64 can be divided by multiple things to gain fractions. You could divide it by 2 repeatedly until arriving to a fraction wherein you couldn’t split anymore.
Ex.) 48/64 = 24/32 = 12/16 = 6/8 = 3/4
All of the above answers are equivalent to 48/64.
An easier way to reach the final answer of 3/4 would be to find the greatest common factor of 48/64. You can divide both by 16 and then get to 3/4.

Hope this helps!

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A square field has an area of 81 square yards. How long is each side of the field? Show your work. Ⓐ 3 yd Ⓒ 18 yd Ⓑ 9 yd Ⓓ 36 yd

MAXImum [283]

Answer:

Each side of the field is 9 yards long.

The correct answer is Ⓑ 9 yd.

Step-by-step explanation:

Given:

A square field has an area of 81 square yards.

Now, to get the length of each side of the field.

As, the square field is having an area of 81 square yards.

Now, to get the side of the square field we put formula:

$Area=(side)^2\\\\81=(side)^2\\\\Using\ square\ root\ on\ both\ sides:\\\\9=side\\\\Side=9\ yards.$

Therefore, each side of the field is 9 yards long.

The correct answer is Ⓑ 9 yd.

8 0

3 years ago

11+5+3x2+8x1= What is the answer?

eimsori [14]

Answer – 30
Solving for 11 + 5 + 3 x 2 + 8 x 1
Using the Order of Operations – BODMAS
Multiplication is prioritized above addition
Therefore, 11 + 5 + 3 x 2 + 8 x 1
= 11 + 5 + (3 x 2) + (8 x 1)
= 11 + 5 + 6 + 8
= 30

4 0

3 years ago

You had $23 to spend on five raffle tickets. After buying them, you had $8.

Sophie [7]

Answer:3

Step-by-step explanation:

23-8= 15

15/5=3

5 0

3 years ago

Read 2 more answers

An experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. How man

zheka24 [161]

Answer:

43,680 ways.

Step-by-step explanation:

We have been given that an experiment involves 16 participants. From these, a group of 4 participants is to be tested under a special condition. We are asked to find the number of groups of 4 participants that can be chosen, assuming that the order in which the participants are chosen is irrelevant.

We will use permutations formula to solve our given problem.

$^nP_r=\frac{n!}{(n-r)!}$

For our given problem $n=16$ and $r=4$ .

$^{16}P_4=\frac{16!}{(16-4)!}$

$^{16}P_4=\frac{16!}{12!}=\frac{16*15*14*13*12!}{12!}=16*15*14*13=43,680$

Therefore, 4 participants can be chosen in 43,680 different ways.

6 0

4 years ago

Twice the sum of a number and 4 is less than 12

Allisa [31]

To find the number you can set up a small equation (x being the number) and solve for x.
It can be written as 2 ( x + 4) < 12
Solve for x to find the number.
2 ( x + 4) < 12
Distribute the 2
2x+8<12
Subtract 8 on both sides
2x<4
Divide by 2 on both sides
x<2

Therefore the number is any number less than 2

~I hope this helps!~

3 0

3 years ago