The smallest possible product of these four numbers is 59.0625
<h3>How to find the smallest possible product of these four numbers?</h3>
The equation is given as:
a + b + c + d = 12
The numbers are consecutive numbers.
So, we have:
a + a + 1 + a + 2 + a + 3 = 12
Evaluate the like terms
4a = 6
Divide by 4
a = 1.5
The smallest possible product of these four numbers is represented as:
Product = a * (a + 1) * (a + 2) * (a + 3)
This gives
Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)
Evaluate
Product = 59.0625
Hence, the smallest possible product of these four numbers is 59.0625
Read more about consecutive numbers at:
brainly.com/question/10853762
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Answer:
Step-by-step explanation:
You have to multiply 30 cents until you get to the total.
Answer:
A and D
Step-by-step explanation:
Since tangent is opposite/adjacent,
Tan 40 in this case would be x/3.8 (i used x because we don't know what the value is)
So, you set it up as an algebra problem
Tan40 = x/3.8
Multiply both sides by 3.8
3.8tan40 = x, Option A
And then, angle E is 50 degrees
So tan 50 = 3.8/x
Multiply both sides by x
tan50x = 3.8
Divide both sides by tan50
x= 3.8/tan50
So, A and D are both correct
The answer is 7.49, 7.5, 7 49/50
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).
0.142 ≈ 0.1
