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Anni [7]
3 years ago
5

A board 30 metres long is to be divided into 2pieces so that the larger piece is 3 metres longer than twice the shorter piece. H

ow long will the pieces be?
Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0
The answer is : 9 and 21
yawa3891 [41]3 years ago
6 0

Answer: 9 and 21

Step-by-step explanation:

board=30m

divide by 2 pieces

one piece, we call it a

b, the other piece is b= 2a+3

a+b=30

a+2a+3=30

3a=30-3

3a=27

a=9

b=21

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) Three pieces of wood are needed to make the border of a garage door (the top and two sides). The
Alexeev081 [22]

Answer:

30ft

Step-by-step explanation:

so first you start with negative 2 and multiply 3 as the formula of the equation then you plug everything in

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2 years ago
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I NEED SOMEONE TO ANSWER THIS QUESTION
Viktor [21]

Answer:

25

Step-by-step explanation:

5=20% of x

0.20x=5

divide both sides by 0.20

x=25

8 0
3 years ago
Molli purchased 7 apples for $3.96. while looking at her receipt, molli divided $3.96 by 7. why might molli perform this calcula
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D) in order to find out how much she paid per apple
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3 years ago
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Rewrite the polynomial in the form ax^2 + bx + C and then identify the values of a, b, and c.
sergejj [24]

Answer:

a = 5\\\\b = -1\\\\c=1

Step-by-step explanation:

Given

-x+5x^2+1

Required

Rewrite and identify a, b and c

The required form is:

ax^2 + bx + c

Equate both expressions

ax^2 + bx + c = -x+5x^2+1

Rewrite as:

ax^2 + bx + c = 5x^2-x+1

Compare the expressions on either sides

a = 5\\\\b = -1\\\\c=1

8 0
3 years ago
A rectangular page is to contain 6 square inches of print. The margins at the top and bottom of the page are to be 2 inches wide
mixer [17]

Answer:

A(t)  =  27.86 in²

Dimensions of the paper:

L =  3.73 in

w = 7.47 in

Step-by-step explanation:

The total area of a rectangular page  A  = ( x + 2)* (y + 4 )         x  is the length and  y the wide. x  and  y  are the dimensions of the print area

The print area of the paper is  A =  6 in²       6 = x*y     y  =  6/x

Then print area as a function of x is

A(x)  =  ( x + 2 ) * ( 6/x + 4 )    ⇒  A(x)  =  6  +  4*x  + 12/x + 8

Taking derivatives on both sides of the equation:

A´(x)  =  4  - 12/x²        A´(x)  =  0     4  =  12 /x²

x²  = 12/4       x =√3    x  =  1.73  in  and   y  =  6 / 1.73

y  =  3.47 in

Then the dimensions of the paper  are.

Length  L =  x  + 2  = 3.73 in      and   w  =  3.47 + 4  = 7.47 in

And the least amount of paper is

A(t)  =  3.73* 7.47  =  27.86 in²

To find out if x = 1.73 is an x coordinate for a minimum we get the second derivative

A´´(x)  =  24/x³    is always positive   A´´(x) > 0  then we have a minimum for A at  x = 1.73

8 0
3 years ago
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