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3 years ago

A cat becomes negatively charged when it is brushed. How does the electric charge on the brush compare to the charge on the cat?

Physics

1 answer:

Karolina [17]3 years ago

4 0

Answer:

The electric charge on the brush is now positive. This means that if the object it light enough (like a balloon) it would stick to the wall.

This is fun science actually.

Explanation:

May I have brainliest please? :)

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I choose D. but I'm not sure if it's right yet. Let me know if it was :)

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3 years ago

Which circuit would have the most electrical power-will mark brainiest if correct

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Answer:

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I’m not sure how to solve this

spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

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3 years ago

Calculating Velocity

m_a_m_a [10]

The average velocity of the object represented by the distance time graph is $0.1\:meter\:per\:second$

The velocity of an object is the change in the distance moved by an object with time.

This could also be related to the rate of change or slope of the graph.

Average velocity = $\frac{change\:in\:distance}{change\:in\:time}$

Average velocity = $\frac{(5-0)}{(50-0}) = \frac{5}{50}=0.1\:meter\:per\:second$

Therefore, the average velocity of the object is $0.1\:meter\:per\:second$

Learn more :brainly.com/question/1378025

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3 years ago

When a satellite is a distance R from the center of the Earth, the force of gravity on the satellite is F. What is the gravitati

Lubov Fominskaja [6]

Gravitational force on a satellite is given by the formula

$F = \frac{GMm}{r^2}$

now here we know that force on the satellite is F when its distance from center of Earth is R

Now the distance from the center of earth will be 3R so the force is given as

$F' = \frac{GMm}{(3R)^2}$

$F' = \frac{GMm}{9R^2}$

so if we compare it with initial value of force then it is

$F' = \frac{F}{9}$

so correct answer is

$(1) F/9$

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