Answer:
<u> </u><u>»</u><u> </u><u>Image</u><u> </u><u>distance</u><u> </u><u>:</u>

- v is image distance
- u is object distance, u is 10 cm
- f is focal length, f is 5 cm

<u> </u><u>»</u><u> </u><u>Magnification</u><u> </u><u>:</u>
• Let's derive this formula from the lens formula:

» Multiply throughout by fv

• But we know that, v/u is M

- v is image distance, v is 10 cm
- f is focal length, f is 5 cm
- M is magnification.

<u> </u><u>»</u><u> </u><u>Nature</u><u> </u><u>of</u><u> </u><u>Image</u><u> </u><u>:</u>
- Image is magnified
- Image is erect or upright
- Image is inverted
- Image distance is identical to object distance.
The angles for the first-order diffraction of the shortest and longest wavelengths of visible light are 22.33 ⁰ and 49.46 ⁰ respectively.
<h3>Angle for the first order diffraction</h3>
The angle for the first order diffraction is calculated as follows;
dsinθ = mλ
sinθ = mλ/d
<h3>For shortest wavelength (λ = 380 nm)</h3>
d = 1/10,000 lines/cm
d = 1 x 10⁻⁴ cm x 10⁻² m/cm = 1 x 10⁻⁶ m/lines
sinθ = (1 x 380 x 10⁻⁹)/(1 x 10⁻⁶)
sinθ = 0.38
θ = sin⁻¹(0.38)
θ = 22.33 ⁰
<h3>For longest wavelength (λ = 760 nm)</h3>
sinθ = (1 x 760 x 10⁻⁹)/(1 x 10⁻⁶)
sinθ = 0.76
θ = sin⁻¹(0.76)
θ = 49.46 ⁰
Learn more about diffraction here: brainly.com/question/16749356
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The answer to that is c hope it helps
The Specific Heat Capacity of silver is 230 J/kgK, melting point is 961.8 C so the difference is 941.8K. Now we simply do q=230J/kgK*16.5kg*941.8K and that is 3 574 131 J