Answer:
Step-by-step explanation:
The number of samples is large(greater than or equal to 30). According to the central limit theorem, as the sample size increases, the distribution tends towards normal. The formula is
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = population standard deviation
n = number of samples
From the information given,
µ = 22199
σ = 5300
n = 30
the probability that a senior owes a mean of more than $20,200 is expressed as
P(x > 20200)
Where x is a random variable representing the average credit card debt for college seniors.
For n = 30,
z = (20200 - 22199)/(5300/√30) =
- 2.07
Looking at the normal distribution table, the probability corresponding to the z score is 0.0197
P(x > 20200) = 0.0197
Answer:
Step-by-step explanation:
I think you are to assume that this is a trapezoid and that the top right angle symbol is missing.
Area = (b1 + b2 ) * h /2
Givens
b1 = 2
b2 = 6.2
h = 3
Solution
Area = (2 + 6.2)* 3 / 2 Combine what is inside the brackets
Area = 8.2 * 3 / 2 Divide by 2
Area = 4.1 * 3 Combine
Answer: Area = 12.3
Answer:
Option D
Step-by-step explanation:
Given that the number of hours of daylight in a city in the northern hemisphere shows periodic behavior over time
Let t be the independent variable and no of hours H(t) be the dependent variable on t.
Maximum H(t) = 14.4 and average =12
Period = 365 days
If we fix a sine curve for this since period is 365, we must have coefficient of t as
![\frac{2\pi}{365} =0.017](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%7D%7B365%7D%20%3D0.017)
So the function H(t) will have sine term as sin 0.017t ... i
Since average = 12, we have
H(t) = 12+a sin 0.017t
for some suitable a.
To find a, use maximum
Maximum is when angle is 90 degrees i.e. when sine value =1
max H(5) = 14.4 = 12+a (1)
a =2.4
Hence correct equation would be'H(t) = 2.4sin(0.017t)+12
OPtion D is right answer.