A^2 + b^2 = c^2
8^2 + b^2 = 12^2
64 + b^2 = 144
b^2 = 144 - 64
b^2 = 80
b = sqrt 80
b = 8.9 ft <===
The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
This is how I would work it out:
1st no. = x+1 2x+10=3(x+1)-7
2nd no. = x 2x+10=3x-4
x=14
1st no. is 15; 2nd no. is 14
To check: 28+10=38; three times the larger is 45; and 38 is 7 less than 45.
Answer:
B) A/l
Step-by-step explanation:
Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other.
Divide l from both sides of the equation:
A = l * w
(A)/l = (l)/l * w
w = A/l
B) A/l is your answer.
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