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stealth61 [152]
3 years ago
15

Complete the recursive formula of the arithmetic sequence -16, -33, -50, -67,...−16,−33,−50,−67,...

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0

Answer:u

Step-by-step explanation:

Shalnov [3]3 years ago
6 0

Answer:

c(1)=-16

c(n)=c(n-1)+-17

Step-by-step explanation:

The first term is -16 and the difference of these numbers is -17.

Got it from Kahn Academy. :)

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V125BC [204]

Answer:

MP is approximately equal to ON because one side of a rectangle is always the same as another side of a rectangle.  

Step-by-step explanation:

4 0
3 years ago
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a
Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0
3 years ago
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Karo-lina-s [1.5K]
From question,
lacy learned 34 recipes in 17 weeks,
so in 1 week she learns = 34/17 =2 recipes,
hence she learns 40 recipes in
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3 years ago
60.3 60.44 witch one is greater
Sindrei [870]
60.44 is greater than 60.3
-you can see this when you subtract 60.3 from 60.44 this would leave a 0.11 which is a positive number.
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4 0
3 years ago
Urgent…. I need help
Firdavs [7]

A.

Step-by-step explanation:

To find out the answer, there is a method that can be used to find out if a line is a function. It is called the vertical line method. And it also has to be per x, One y value has to be there. Analyzing the graphs, the answer should be option A.

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