Answer:
The region represented by the equation is a full sphere of radius √3 centered in the origin of coordinates.
Step-by-step explanation:
<em>In a plane xy, the equation that represents a circle with center in the origin, of radius r is</em>
<em>in R³, or a space xyz, we can represent a sphere with its center in the origin, and of radius r, with the equation</em>
So, in this problem we have that
which means that the sphere has a radius of √3.
<u>Finally, our equation is an inequality</u>, and the sphere is equal to, and less than, the calculated radius.
Therefore, the sphere is "full" from the surface to its center.
5.6*1 2/5 = 5 3/5 * 1 2/5 =28/5 * 7/5 = 196/25 = 784/100 = 7.84 or 7 21/25
Answer:
See below...
Step-by-step explanation:
For a function whose formula is in this pattern:
Amplitude: 
Period: 
Phase Shift: C
In this question, 
Amplitude: 4
Period: 
Phase Shift: 
There is no vertical shift, so the midline is the x-axis whose equation is y = 0.
Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.
The graph is attached.
Answer:
- 1/64 (x+4)² (x-3) (x-4) = 0
Step-by-step explanation:
f(x) = a (x+4)²(x-3)(x-4) ... curve touch (-4,0) and not cross x axis
x=0 f(x) = -3
a (4)² * (-3) * (-4) = -3
a = - 1/64
- 1/64 (x+4)² (x-3) (x-4) = 0
