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alina1380 [7]
2 years ago
15

Please help me!! what is the probability that a yellow (Y) and wrinkled (r) pea will appear from a cross of RrYy x RrYy?

Biology
1 answer:
Kay [80]2 years ago
4 0

Answer:

3/16

Explanation:

This question involves two genes coding for pea shape and pea color. The alleles for yellow color (Y) and round seeds (R) are dominant over the alleles for green color (y) and wrinkled seeds (r).

In this cross between two heterozygotes: RrYy × RrYy, the following allele combinations are produced in the gamete of each parent: RY, Ry, rY and ry. Using these gametes in a punnet square (see attached image), the following offsprings are produced:

9/16 of Round, yellow offsprings (R_Y_)

3/16 of Round, green offsprings (R_yy)

3/16 of Wrinkled, yellow offsprings (rrY_)

1/16 of wrinkled, yellow offsprings (rryy)

Hence, the probability that a yellow (Y) and wrinkled (r) pea will appear from a cross of RrYy x RrYy is 3/16.

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2 years ago
In the world of purple people eaters, one eye (E) and one horn (H) are dominant traits. Purple people eaters
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Answer:

3

Explanation:

Male ; EeHh

Female ; EeHh

Then,

possible gametes for each = EH / Eh / eH / eh

where,

                            EH                    Eh                   eH                    eh

EH                      EEHH               EEHh              EeHH               EeHh

                     <em>   One eye            One eye         One eye          One eye</em>

<em>                         One horn          One horn        One horn        One horn</em>

<em />

Eh                      EEHh                 EEhh               EeHh                Eehh

                       <em>One eye              </em><em>One eye</em><em>         One eye          </em><em>One eye</em><em> </em>

                        <em>One horn            </em><em>Two horn</em><em>       One horn         </em><em>Two horn</em>

eH                     EeHH                  EeHh              eeHH                eeHh

                        <em>One eye             One eye         </em><u><em>Two eye</em></u><em>          </em><u><em>Two eye </em></u>

                        <em>One horn            One horn        </em><u><em>One horn</em></u><em>        </em><u><em>One horn</em></u><em> </em>

eh                     EeHh                   Eehh                eeHh                eehh

                      <em>One eye              </em><em> One eye    </em><em>      </em><u><em>Two eye</em></u><em>          </em><u><em> Two eye </em></u>

<em>                       One horn              </em><em>Two horn </em><em>       </em><u><em>One horn</em></u><em>         </em><u><em>Two horn </em></u>

<u><em /></u>

Therefore,

One eye, one horn:One eye, two horn:<u>Two eye, one horn</u>:Two eye,two horn

is,

9 : 3 : <em><u>3 </u></em>: 1

This ration proves that the above working is correct and is dihybrid cross.

6 0
3 years ago
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olga55 [171]
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Restriction enzyme HinfI cleaves a five nucleotide DNA sequence GA(A/T)TC. The ambiguity in the central position - (A/T) - means
Afina-wow [57]

Answer:

C) 2.0 kb

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Also, it is given that probability of occurrence of either A or T at 3rd position is equal which means that the probability at that particular position will be 2/4 = 1/2.

Now, GA(A/T)TC is the DNA sequence where Restriction enzyme HinfI cleaves so the total probability of an average HinfI cleavage fragment will be = 1/4 x 1/4 x 1/2 x 1/4 x 1/4 = 0.00195 = 0.2 i.e. 2 kb.

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Which two hormones closely control levels of calcium in the blood?
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Explanation:

4 0
3 years ago
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