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alina1380 [7]
3 years ago
8

1. Which point is located at (-2,-6)

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0

<u><em>Explanation: Quadrant is a quarter if the coordinate plane. Origin is a point of intersection of the two axes. X-coordinate is a horizontal position. Y-coordinate is a vertical position. X-axis is a horizontal axis. Y-axis is a vertical axis.</em></u>

<u><em>Answer: </em></u>

<u><em>1. K: (-2,-6) it should be found in Quadrant III. Answer just look like this: → K.</em></u>

<u><em>2. N: (0,-4) it should be found in Quadrant IV. J: (4,-4) it should be found in Quadrant IV. F: (7,-5) it should be found in Quadrant IV. Answer just  like this: → N,J, and F.</em></u>

<u><em>3. (-3,1) it should be found in Quadrant ll.</em></u>

<u><em>Hope this helps!</em></u>

<u><em>Thanks!</em></u>

<u><em>Have a great day!</em></u>


andriy [413]3 years ago
7 0
1 k
2 n j f
3 (-3,1)
that what i think they are
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Step-by-step explanation:

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Answer:

When dividing two values with the same base, we simply subtract the first exponent by the second and keep the original base. 3^3-6=3^-3. This equals out to be 1/27.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle
ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

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The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

A=w(2w+6)

We can also substitute 40 in for A as it's given in the question.

40 = w(2w+6)

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

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We can make the equation simpler by dividing both sides by 2.

20 = w^2+3w

Subtracting both sides by 20 will make the left-hand side 0.

0=w^2+3w-20

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}

w= \frac{-3\pm\sqrt{9+80}}{2}

w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}

Since the second solution results in a negative number, it cannot be the length of w.

w=\frac{-3+\sqrt{89}}{2}\approx3.217

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

l=2(3.217)+6

l=12.434

The length of this rectangle is 12.434 cm.

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Melissa mows many lawns in her neighborhood. She mows lawns for $95 per lawn. She also offers full landscape maintenence for $12
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