Which number represents the opposite of -25

A graph titled Cost of a Lunch in a School's Cafeteria has Days since school started on the x-axis and cost of lunch (dollars) o

Rufina [12.5K]

The true statement about the graph's slope is (c) Its slope is zero.

<h3>How to determine the true statement?</h3>

From the question, we have:

A horizontal line is at y = 2.5.

The horizontal line implies that the cost of lunch do not change

Horizontal lines have a slope of 0

Hence, the true statement about the graph's slope is (c) Its slope is zero.

Read more about slope at:

brainly.com/question/3493733

#SPJ1

8 0

2 years ago

An exit poll in an election is a survey taken of voters just after they have voted. One major use of exit polls has been so that

3241004551 [841]

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

7 0

3 years ago

PLZ HELP HURRRY. Select the correct answer. which statement is true about the slope of the graphed line?

netineya [11]

Answer:

B

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The headlights of an automobile are set such that the beam drops 3 in for each 32 ft in front of the car. What is the angle (giv

Anastaziya [24]

Answer:

0.4476 degrees.

Step-by-step explanation:

Let θ be the angle between the beam and the road. The given values form a right triangle with the distance that the beam drops ( h=3 in) being the side opposite to θ and the distance in front of the car (x=32 ft or x=384 in) being the side adjacent to θ.

Therefore, θ is given by:

$tan^{-1}(\theta) = \frac{h}{x}\\tan^{-1}(\theta) = \frac{3}{384}\\ tan^{-1}(\theta) = \frac{1}{128}\\\theta=0.4476^o$