Answer:
(1)
And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:


And replacing we got:

And the width for this case would be 15.8 in
Step-by-step explanation:
For this case we know that the photo is rectangular. Let's define:
x = the width, y= the length
And we know that the perimeter is given by:
(1)
And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:


And replacing we got:

And the width for this case would be 15.8 in
Calculating the area and the perimeter The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle.
I Believe it is 80% but I am not sure
Answer:
x + 10
Step-by-step explanation:
X is used to represent a variable or any number. This letter can be changed if you'd like
Answer:
Yes
Step-by-step explanation:
1 : The athlete's hands push the medicine ball forward. The medicine ball pushes the athlete's hands backward.
2: Friction
3: The first pair of action-reaction force pairs is: foot A pushes ball B to the right; and ball B pushes foot A to the left. The second pair of action-reaction force pairs is: foot C pushes ball B to the left; and ball B pushes foot C to the right