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musickatia [10]
3 years ago
12

What is the density of a piece of wood that has a mass of 17.5 grams and a volume of 20 cm'?

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0
0.875 is the density for this question
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At noon Ada and Kent had gallons of lemonade left at their lemonade stand. The next 3/8 customer bought of the remaining lemonad
Stolb23 [73]

Answer:

2

Step-by-step explanation:

Which represents the solution set of the inequality 5x-9 < 21? a. x < 12/5 b. x > 12/5 c. x > 6 d. x < 6

5 0
3 years ago
What is the answer ​
Reika [66]

Answer:

35 mi²

Step-by-step explanation:

Let's subdivide the figure, as shown.

The lower part is a rectangle whose area is (5 mi)(18 mi) = 90 mi².

The upper part is a trapezoid whose area is found by averaging the length and multiplying the result by the width (8 mi - 5 mi), or 3 mi.

Area of trapezoid:

     12 mi + 18 mi

  ------------------------  =  15 mi             Width of trapezoid = 3 mi

                2

Thus, the area of the trapezoid is (3 mi)(15 mi) = 45 mi²

and the total area of the entire figure is

45 mi² + 90 mi² = 135 mi²

3 0
2 years ago
Find the outlier of the data set?<br> 40, 62, 47, 68, 12, 78, 49, 65, 49, 52, 63
ss7ja [257]
The outlier is gonna be 12
5 0
3 years ago
Read 2 more answers
What is the end behavior for f(x)=4x^4+2x^3-13x^2-14x+24?
Tpy6a [65]

Answer:

This means that f(x)→∞ as x→−∞ and f(x)→∞ as x→∞.

Step-by-step explanation:

Since the leading term of the polynomial (the term in a polynomial which contains the highest power of the variable) is x4, then the degree is 4, i.e. even, and the leading coefficient is 1, i.e. positive.

This means that f(x)→∞ as x→−∞ and f(x)→∞ as x→∞.

8 0
3 years ago
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
vitfil [10]

Answer:

a) The minimum head breadth that will fit the clientele = 4.105 inches to 3d.p = 4.1 inches to 1 d.p

b) The maximum head breadth that will fit the clientele = 8.905 inches to 3 d.p = 8.9 inches to 1 d.p

Step-by-step explanation:

This is normal distribution problem.

A normal distribution has all the data points symmetrically distributed around the mean in a bell shape.

For this question, mean = xbar = 6.1 inches

Standard deviation = σ = 1 inch

And we want to find the lowermost 2.3% and uppermost 2.3% of the data distribution.

The minimum head breadth that will fit the clientele has a z-score with probability of 2.3% = 0.023

Let that z-score be z'

That is, P(z ≤ z') = 0.023

Using the table to obtain the value of z'

z' = - 1.995

P(z ≤ - 1.995) = 0.023

But z-score is for any value, x, is that value minus the mean then divided by the standard deviation.

z' = (x - xbar)/σ

- 1.995 = (x - 6.1)/1

x = -1.995 + 6.1 = 4.105 inches

The maximum head breadth that will fit the clientele has a z-score with probability of 2.3% also = 0.023

Let that z-score be z''

That is, P(z ≥ z'') = 0.023

Using the table to obtain the value of z''

P(z ≥ z") = P(z ≤ -z")

- z'' = - 1.995

z" = 1.995

P(z ≥ 1.995) = 0.023

But z-score is for any value, x, is that value minus the mean then divided by the standard deviation.

z'' = (x - xbar)/σ

1.995 = (x - 6.1)/1

x = 1.995 + 6.1 = 8.905 inches

6 0
3 years ago
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