Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e.,
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
Let x be the amount of cement and y be the amount of sand. If <span>the ratio of cement to sand for mortar is 1:3, then
and y=3x.
</span>
So, if <span>Sandy puts in x=7 shovels of cement, then she puts
shovels of sand.
</span><span>
</span><span>
Answer: 21 shovels of sand.
</span>
Answer:
0.609 / week ( to nearest thousandth)
or you can state it as 60.9% of a book per week
Step-by-step explanation:
That would be 14/23 = 0.609 / week
Answer:
i hope this works. Feel better soon!
Step-by-step explanation:
1.SAS 2 AAS 3 SAS 4 NOT CONGRUENT 5 SSS 6 ASA
7. ∠BAC≅∠EDC given, BC ≅ CE GIVEN ∠ACB≅∠DCE VERTICAL ANGLES, ΔABC≅ΔDEC AAS
8. ∠PQR≅∠TSR GIVEN R IS MIDPOINT OF PT GIVEN PQ≅ST GIVEN ΔPQR≅ΔTSR HYPOTENUSE LEG THEORUM
9. AC BISECTS BCD GIVEN ∠ABD≅∠ADC GIVEN ∠ACB≅∠ADC BISECTED ANGLES AC≅AC REFLEXIVE PROPERTY OF CONGRUENCE ΔABC≅ΔADC ASA AB≅AC SAME SIDES OF CONGRUENT TRIANGLES
