Hello :
<span>g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
Answer:
see the explanation
Step-by-step explanation:
we know that
The y-intercept is the value of the function y when the value of x is equal to zero
Part 1) we have

For x=0
substitute in the linear equation and solve for y


therefore
The y-intercept is the point (0,-6)
Part 2) Find the y-intercept of the function represented in the graph
Looking at the graph
For x=0
Find the value of y in the graph
The value of y is equal to y=1
therefore
The y-intercept is the point (0,1)
18. S=r^2-t^2
S+t^2=r^2
r=sqrt(S+t^2)
20. Tan 18=x/12
x=12×Tan 18
x=3.899036355
x=3.90
I hope this helps.
(i) Slope is 
(ii) x - intercept is 
(ii) y - intercept is 
Explanation:
The given equation is 
We need to determine the slope, x - intercept and the y - intercept
(i) Let us determine the slope of the equation.
Since, the equation is of the form
where m is the slope
Thus, comparing the equation
with the general form
, the slope is 2.
Thus, slope is 
(ii) Now, we shall determine the x - intercepts.
The x - intercept can be determined by substituting
in 
Thus, we have,



Thus, the x - intercept is 
(iii) The y - intercept can be determined by substituting
in 
Thus, we get,



Thus, the y - intercept is 
C
-x=-y-10 = x=y+10
x is 10 bigger than y
x+y=12
C