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ArbitrLikvidat [17]
3 years ago
11

Simplify the expression 2(10)+2(x-2)

Mathematics
2 answers:
enyata [817]3 years ago
8 0
The answer is 2x+16........ hope this helps
FrozenT [24]3 years ago
4 0

Answer:

16 + 2x

Step-by-step explanation:

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Ln (x-2) +ln (2x-3)=2ln x
goblinko [34]
D:x-2\ \textgreater \ 0 \wedge 2x-3\ \textgreater \ 0 \wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2 \wedge x\ \textgreater \ \dfrac{3}{2}\wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2\\\\
\ln (x-2) +\ln (2x-3)=2\ln x \\
\ln (x-2)(2x-3)=\ln x^2\\
(x-2)(2x-3)=x^2\\
2x^2-3x-4x+6=x^2\\
x^2-7x+6=0\\
x^2-x-6x+6=0\\
x(x-1)-6(x-1)=0\\
(x-6)(x-1)=0\\
x=6 \vee x=1\\
1\not \in D\\
\boxed{x=6}
4 0
3 years ago
HELP PLEASE THIS IS DUE IN 30 MIN PLEASE HELP URGENT
Oxana [17]

Answer:

12.5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An aquarium is leaking water at the rate of three quarts in 4 days.How many quarts are leaked in 1 week?How many days does it ta
Simora [160]

Answer:

\frac{21}{4} quarts

12 days

Step-by-step explanation:

Given that:

Amount of water leaked in 4 days = 3 quarts

To find:

Number of quarts leaked in 1 week?

Number of days taken for the leakage of 9 quarts of water?

Solution:

We can simply use unitary method or the ratio to find the answers of the questions asked in the statement.

As per question statement:

Amount of water leaked in 4 days = 3 quarts

Dividing by 4 on both sides:

Amount of water leaked in 1 day = \frac{3}{4} quarts

Multiplying by 7 on both sides:

Amount of water leaked in 7 days = \frac{3}{4}\times 7 = \frac{21}{4} quarts

Number of days taken for the leakage of 3 quarts = 4 days

Multiplying by 3 on both sides:

Number of days taken for the leakage of 3 \times 3 = 9 quarts = 4 \times 3 = <em>12 days</em>

6 0
3 years ago
If f(x) = 4x + 8 and g(x) = (x+4,<br> what is (fºg)(12)?
svetlana [45]

Answer:

72

Step-by-step explanation:

f(x) = 4x+8\\g(x) = x + 4\\\\1. f(g(x)) = 4(x+4) + 8\\2. f(g(x)) = 4x + 16 + 8\\3. f(g(x))=4x + 24\\\\4. f(g(12)) = 4(12) + 24\\5. f(g(12)) = 48 + 24 = 72\\

To do these, you have to place the entire function inside the parent function's variables.

You are inputting the value of the function g(x) into f(x)

4 0
3 years ago
4 - x + <img src="https://tex.z-dn.net/?f=6%5E%7B2%7D" id="TexFormula1" title="6^{2}" alt="6^{2}" align="absmiddle" class="latex
Lemur [1.5K]

Answer:

x ≤ 19

Step-by-step explanation:

The instructions here are probably "solve for x."  Please include them.

4 - x + 6^2 ≥  21

becomes 4 - x + 36 ≥  21

Now combine like terms.  4 and 36 combine to 40:  40 - x ≥ 21, and so:

19 - x ≥ 0

Adding x to both sies results in

x ≤ 19

Please, include the instructions when you post a question.  Thanks.

3 0
3 years ago
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