length = 3234 m and width = 1614 m
let the width = w then length = 2w + 6
Perimeter = 2 ( length + width )
= 2 (2w + 6 + w ) = 2 ( 3w + 6 ) = 6w + 12
given perimeter = 9696 the equating gives
6w + 12 = 9696
subtract 12 from both sides
6w = 9696 - 12 = 9684
divide both sides by 6
w = = 1614
width = 1614 m and length = (2 × 1614 ) + 6 = 3234 m
<u>Answer:</u>
The height of the tower nearby the pole is 102 m.
<u>Solution:</u>
Given,
Height of the pole = 3.5 m
Length of the shadow of the pole = 1.47 m
Length of the shadow of the tower nearby = 42.75 m
Let us assume the height of the tower as x
On solving for x we get,
On rounding off to the nearest meter we get,
x=102 m
The height of the tower is 102 meter.