Let d = number of dimes, q = number of quarters
<span>Sally has 20 coins in her piggy bank, so </span>
<span>d + q = 20 </span>
<span>The total amount of money is $3.05. </span>
<span>Use the value of each coin multiplied by its number to get total value </span>
<span>.10d + .25q = 3.05 </span>
<span>multiply everything by 100 to clear the decimal places </span>
<span>10d + 25q = 305 and </span>
<span>d + q = 20 </span>
<span>solve the second equation above in terms of either d or q - lets do d </span>
<span>d = 20 - q </span>
<span>sub that into the first equation </span>
<span>10d + 25q = 305 </span>
<span>10(20 - q) + 25q = 305 </span>
<span>200 - 10q + 25q = 305 </span>
<span>15q = 105 </span>
<span>q = 105/15 = 7 </span>
<span>and from above </span>
<span>d = 20 - q = 20 - 7 = 13 </span>
<span>so, there are 13 dimes and 7 quarters </span>
<span>verify with orig problem </span>
<span>13 + 7 = 20, OK, and $1.30 + $1.75 = $3.05
</span>
First expand the parentheses:-
96x + 18 - 6 + 8x + 25 = 0
104x = -18 + 6 - 25 = -37
x = -37 / 104 = -0.3558
16 ounces is 1 pound.
So 1 ounce will be 1/16 pound.
750 × 1/16
Answer:
When A and B are not both zero, the graph of Ax + By = C is always a line. The graph of Ax + By = C, where A and B are not both zero, is a line. Divide both sides by B. Because the form Ax + By = C can describe any line, it is called the standard form of an equation for a line.
Hope this helps you!
(f·g)(x) is x^5 - 5x^4 + 4x³ - x² + 5x - 4
Step-by-step explanation:
- Step 1: Given, f(x) = x² - 5x + 4 and g(x) = x³ - 1 Find (f·g)(x)
(f·g)(x) = f(x)·g(x) = (x² - 5x + 4)(x³ - 1)
= x^5 - 5x^4 + 4x³ - x² + 5x - 4
= x^5 - 5x^4 + 4x³ - x² + 5x - 4
