Answer: the average distance between the parabola is 2000
Step-by-step explanation:
Given that;
y = 30x(20 - x) and the x-axis on the interval [0, 20]
f(x) = y = 30x(20 - x); [0, 20] and a=0, b=20
the average distance between the parabola will be
Average value = 1/20-0 ²⁰∫₀ 30x(20-x) dx
= 1/20 ²⁰∫₀ (600x-30x²) dx
= 1/20 [(600x)/2 - (30x³)/3]₀²⁰
= 1/20 [300x - 10x³]₀²⁰
inputting the limits, we get
= 1/20 [(300 × 20 × 20 - 10 × 20 × 20 × 20) - 0 - 0]
= 1/20 ( 120000 - 80000)
= 0.05 × 40000
<h2>= 2000</h2>
Therefore the average distance between the parabola is 2000
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Answer:
your correct
Step-by-step explanation:
you did the explanation
10.5+(10.5*.4)=10.5+(4.2)=14.7lbs after the first month
Answer:
6m
Step-by-step explanation:
This is the commutative property of addition
This property is the idea of adding any two numbers in any order you want. For example: 2+3 = 3+2 = 5
In this problem, we have 2.5+12.66 the same as 12.66+2.5
