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Dmitrij [34]
3 years ago
11

Plz help me I rlly need it!

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0
1. 9 is the mode
2. 17.7 is the mean
3. 25.5 is the median
4. mean > median
5. 28 is the range
You might be interested in
Leo's age is three times Stan’s age. In five years, Leo will be twice as old as Stan. How old is each now?
aleksandr82 [10.1K]

Answer:


Step-by-step explanation:

L=3S

In 5 years,

L+5=2(S+5)

L+5=2S+10

L=2S+5

 Substituting from above,

3S=2S+5

S=5

So then,

L=3(5)

L=15

6 0
3 years ago
How many solutions does the nonlinear system of equations graphed below
yan [13]

Answer:

D. zero

Step-by-step explanation:

Since the graphs do not intersect, there are zero solutions.

6 0
3 years ago
A4(3a2 - 2a + 1)<br> What’s the product
guajiro [1.7K]

The answer is

3a^6 - 2a^5 + a^4

6 0
2 years ago
Let SSS represent the number of sunflower plants and LLL represent the number of lily plants Ezra's water supply can water.
Fantom [35]

Answer:

Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

Step-by-step explanation:

Given the inequality function

0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;

0.7S+0.5L≤11

0.7S+0.5(10)≤11

0.7S+5≤11

Taking 5 to the other side:

0.7S≤11-5

0.7S≤6

S≤6/0.7

S≤8.57

This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

3 0
3 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
Read 2 more answers
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