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3 years ago

{0.23,19%1/5} Order each set of numbers from least to greatest show work

1 answer:

4 0

First you have to change them all to the same form, so you have to pick one out of them, so for instance you could pick percent which would be; 23%, 19%, and 20%, so from least to greatest it would be; 19%, 20%, and 23%. Hope this helps!

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8a+3.28=46.28 solve for a please ik I already asked but I need to pass this test thank you :)

KonstantinChe [14]

Answer:

A=5.375

Step-by-step explanation:

46.28-3.28= 43

43÷8= 5.375

I hope this helps

4 0

2 years ago

Find f. (Use C for the constant of the first antiderivative and D for the constant of the second antiderivative. f"(x) = 2x + 9e

ad-work [718]

Answer:

$f(x)=\frac{x^3}{3}+9e^x+Cx+D$

Step-by-step explanation:

The function F(x) is an antiderivative of the function f(x) on an interval I if

F′(x) = f(x) for all x in I.

The function F(x) + C is the General Antiderivative of the function f(x) on an interval I if F′(x) = f(x) for all x in I and C is an arbitrary constant.

The Indefinite Integral of f(x) is the General Antiderivative of f(x).

$\int {f(x)} \, dx =F(x)+C$

To find the first antiderivative you must integrate the function $f''(x) = 2x + 9e^x$

$f'(x)=\int { 2x + 9e^x} \, dx \\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:2xdx+\int \:9e^xdx = x^2+9e^x\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\x^2+9e^x+C$

To find the second antiderivative you must integrate the function $f'(x) =x^2+9e^x+C$

$f(x)=\int {x^2+9e^x+C} \, dx\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int \:x^2dx+\int \:9e^xdx+\int \:Cdx= \frac{x^3}{3}+9e^x+Cx\\\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\\\\frac{x^3}{3}+9e^x+Cx+D$

Therefore,

$f(x)=\frac{x^3}{3}+9e^x+Cx+D$

8 0

2 years ago

Help quickly! 10 points!

german

The answer is vertex

6 0

3 years ago

The sum of the lengths of two sides of a triangle is always greater then the length of the third side.

Tanya [424]

Answer:Triangle Inequality Theorem. The sum of the lengths of any two sides of a triangle is greater than the length of the third side

Step-by-step explanation:

5 0

3 years ago

) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp

Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

Let $\bar X$ = sample average salary

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = mean salary = $1.5 million

$\sigma$ = standard deviation = $0.9 million

n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( $\bar X$ > $1.1 million)

P( $\bar X$ > $1.1 million) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ > $\frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} }$ ) = P(Z > -8.89) = P(Z < 8.89)

Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0

3 years ago