Answer:
d = 
Step-by-step explanation:
Given that W varies jointly as L and d² then the equation relating them is
W = kLd² ← k is the constant of variation
To find k use the condition W = 140 when d = 4 and L = 54, thus
140 = k × 54 × 4² = 864k ( divide both sides by 864 )
= k , that is
k = 
W =
Ld² ← equation of variation
Multiply both sides by 216
216W = 35Ld² ( divide both sides by 35L )
= d² ( take the square root of both sides )
d = 
Answer:
B) no, because the corresponding angles are not congruent
Step-by-step explanation:
Similar triangles must have proportional sides, as well as congruent corresponding angles. In this instance, we can see that the angles are not <em>congruent</em>, and so there is no need to solve for proportion.
~
The equation of parabola is
. If a is positive and
is always greater than zero or equal to zero, then x is also greater or equal to zero. This means that parabola is determined for non-negative x and for all real y.
Tha canonical equation of parabola is
, where p>0. The branches of this parabola go up in positive y-direction. When you change x to y and y to x, then the branches of parabola go in positive x-direction, that is right.
Answer: correct choice is A.
1 over 3 should be the answer I think
Answer:

Step-by-step explanation:
- If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
- When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)
<u>using these information</u>:
g(x)=ln2x then g'(x)=
h(x)=In(3x - 1) then h'(x)=![\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}](https://tex.z-dn.net/?f=%5Cfrac%7B%283x-1%29%27%7D%7B3x-1%7D%20%3D%5Cfrac%7B3%7D%7B3x-1%7D%3C%2Fp%3E%3Cp%3Ef%27%28x%29%3Dg%27%28x%29%20-%20h%27%28x%29%20%3D%5Btex%5D%5Cfrac%7B1%7D%7Bx%7D%20-%20%5Cfrac%7B3%7D%7B3x-1%7D%20%3D%5Cfrac%7B-1%7D%7B3x%5E2-x%7D)