Answer:
x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically
x+y+2=-5 equation 1
-2x-y+2=-1 equation 2
x-2y-2=0 equation 3
Add equation 1 + 2+ 3
x+y+2=-5 + -2x-y+2+1 + x-2y-2
x+y+2= -7+2+1-2x+x+y
x+y+2= -4-x+y
x+y+2+4+x-y= 0
2x+6= 0
2x= -6
divide both side by 2
x= -3
from equation 1 insert x
x+y+2=-5
since x=-3
then, -3+2+y= -5
-1+y= -5
y= -5+1
y= -4
Step-by-step explanation:
Start by doing the binomial expansion of (x+y)^6 where x represents success. This is
(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)
We are interested in the x^3y^3 term which represents exactly 3 sucesses. Since the probalbility of sucess and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is
20/64 = .3125 which is 31.25%
Answer:
2x+9y=18
Step-by-step explanation:
Distribute the denominator
y=-2/9x+2
9y=-2x+2
9y+2x=2
im sorry if this is wrong
Step-by-step explanation:
- natural numbers, whole numbers, and integers zero is the additive identity
- 1 is the multiplicative identity.
in case of rational numbers.
<h2>hope it helps.</h2><h2>stay safe healthy and happy.</h2>
japones ^^
look you have to multiply
8 cm x 6cm
20cm x 6 cm
and the answer that comes out of the multiplication is the correct one
