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andrezito [222]
3 years ago
7

How do you use a model to show 3.1 = 3.10

Mathematics
1 answer:
n200080 [17]3 years ago
5 0
Because every number with the decimal point have a zero infinit so it's not matter they're are same
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The division algorithm states that if​ p(x) and​ d(x) are polynomial functions with d left parenthesis x right parenthesis not e
katrin [286]

Answer:

In a division algorithm, p(x) refers to the dividend polynomial, d(x) refers to the divisor polynomial, q(x) refers to the quotient polynomial and r(x) refers to the residula polynomial.

The division algorithm is defined as

p(x)=d(x) \times q(x) +r(x)

Where p(x)\geq d(x) and d(x) \neq 0, other wise the algorithm won't be defined.

So, the complete paragraph is: "if p(x) and d(x) are polynomial functions with d(x)\neq 0 and the degree of d(x) is less than or equal to the degree of p(x), then there exist unique polynomial functions q(x) and r(x) such that  p(x)=d(x) \times q(x) +r(x).

7 0
3 years ago
Read 2 more answers
Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan
inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}

                         = \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \  \ \\\\

                                                                                                       k= 2,3..........10For option B:

P(X=k | X \geq 2 ) =  \sum^{10}_{i=2}  \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}

                                                                                                k= 2,3, 4.........10

8 0
3 years ago
If you place a 24-foot ladder against the top of a 22-foot building, how many feet will the bottom of the ladder be from the bot
Naddika [18.5K]

Answer:

9.6

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

Plug in the knowns

a² + 22² = 24²

Subtract 22² from both sides

a² = 24² - 22²

a² = 576 - 484

a² = 92

Take the square root of both sides

a = 9.591663046625438

Rounded

a = 9.6 ft

8 0
3 years ago
Read 2 more answers
Which expressions are equivalent to (5⋅x)⋅3 ? Drag and drop the equivalent expressions into the box.
marysya [2.9K]
<h2>Greetings!</h2>

Answer:

3⋅(5⋅x)

5⋅(x⋅3)

15x

Step-by-step explanation:

As the values are inside the brackets, it does not matter what side the (x3) is on, so 3⋅(5⋅x) is equivalent.


Multiplying the contents of the brackets in the third one (x * 3) by 5 gives the same value as 3 * (x * 5) so 5⋅(x⋅3) is also equivalent.


On multiplying the brackets out:

5 * x = 5x

5x * 3 = 15x

So 15x is also equivalent.


<h2>Hope this helps!</h2>
3 0
3 years ago
A study on how circus ticket pricing influences ticket sales shows that there is an average increase of 4 people for every $3 de
____ [38]
Let the price of a ticket be originally T dollars, and the number of clients be N.

let the price decrease by x  3-dollars.

"there is an average increase of 4 people for every $3 decrease on the price of the ticket."

means:

if the price is decreased by 1-3$:
 then N become N+4, and T becomes T-3    


if the price is decreased by 2-3$:
 then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3    

 So if the price is decrease by x-3 dollars:

N  becomes N+4x, and T becomes T-3x


"A circus owner sells an average of 340 tickets when the price of a ticket is $75."

In this case N=340, and T=75$

If the owner does not change the price ticket, x=0, the revenue is 340*75,

If the owner decreases the price of the tickets by x-3$, then the revenue will be 
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,

If R is the function of the revenue depending on x, then 

R(x)=(340+4x)(75-3x) dollars

 
Answer: R(x)=(340+4x)(75-3x) dollars

8 0
3 years ago
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