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Fudgin [204]
3 years ago
5

Container A has 200 L of water, and is being filled at a rate of 6 liters per minute. Container B has 500 L of water, and is bei

ng drained at 6 liters per minute. How many minutes, m, will it take for the two containers to have the same amount of water?
Mathematics
1 answer:
pickupchik [31]3 years ago
6 0

Answer:

25 minutes

Step-by-step explanation:

Container A : 200 + 6x = y

Container B: 500 - 6x = y

y = final volume of water

x = number of minutes

Final volume is same so:

200 + 6x = 500 - 6x\\12x = 300\\x = 25

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Answer:

a) 0.83 = 83% probability that a LED screen will meet specifications.

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Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

45% from supplier B1, 30% from supplier B2, and the rest from supplier B3.

So 100 - (45 + 30) = 100 - 75 = 25% from supplier B3.

a) Find the probability that a LED screen will meet specifications.

95% of 45%(supplier B1)

80% of 30%(supplier B2)

65% of 25%(supplier B3). So

p = 0.95*0.45 + 0.8*0.3 + 0.65*0.25 = 0.83

0.83 = 83% probability that a LED screen will meet specifications.

b) Calculate the probability that a LED screen that meets specifications was sent by the second supplier.

Conditional probability.

Event A: Meets specifications.

Event B: Sent by second supplier.

0.83 = 83% probability that a LED screen will meet specifications.

This means that P(A) = 0.83

Meets specifications and is sent by the second supplier.

80% of 30%, so

P(A \cap B) = 0.8*0.3 = 0.24

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.24}{0.83} = 0.2892

0.2892 = 28.92% probability that a LED screen that meets specifications was sent by the second supplier.

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