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2 years ago

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Tickets for admission to a high school football game cost $3 for students and $5 for adults. During one game, $2995 was collecte

d from the sale of 729 tickets.
a. Writing a System. Write and solve a system of linear equations to find the number of tickets sold to students and the number of tickets sold to adults.

b. Drawing a Graph. Graph the system of linear equations. Use the
graph to determine whether your answer to part (a) is reasonable.

1 answer:

Wittaler [7]2 years ago

3 0

The solution to the equation is (325, 404) which is the point of intersection.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

Let x represent the number of student tickets and y represent the number of adult tickets.

It is given by the equation:

x + y = 729 (1)
3x + 5y = 2995 (2)

The solution to the equation is (325, 404) which is the point of intersection.

Find out more on Linear equation at: brainly.com/question/14323743

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The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.

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Consider the provided information.

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Thus, n = 12, $\bar x=36800$ σ = 5000

degrees of freedom = n-1 = 12-1 = 11

$H_0: \mu = 33700\ and\ H_a: \mu \neq 33700$

Formula to find the value of z is: $z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}$

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3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

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Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

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Where k=Proportionality constant

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$C=ln 200$

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$ln y=kt+ln 200$

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$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

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Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

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4 years ago