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3 years ago

Write an equation, please help

Mathematics

2 answers:

Mrac [35]3 years ago

6 0

Answer:

5\6x-2

Step-by-step explanation:

Y=(10-6x)\5

Y= 2-6\5x

Slope of line 1 = -6\5

Slope of line 2*(slope of line 1 )= -1

Slope of line 2 *-6\5=-1

Slopes of line 2 = 5\6

(X-x0)m = y-y0

(X-6)*5\6=y-3

5\6x -5 = y-3

Y= 5\6x -2

ale4655 [162]3 years ago

4 0

Answer:

y = -6/5x + 2

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A cylindrical can, open at the top, is to hold 840 cm3 of liquid. Find the height and radius that minimize the amount of materia

ycow [4]

Answer:

the radius of the base is equal to $x=2\sqrt[3]{\frac{105}{\pi } }$

And the height is equal to:

$y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }$

Step-by-step explanation:

We write the volume function

$f(x,y)=840=\pi x^{2} y$ where x is the radius of the base and y is the height of the cylinder

$y=\frac{840}{\pi x^{2} }$

The surface of a cylinder is given by

$S(x)=\pi x^{2} +2\pi xy=\pi x^{2} +\frac{1680}{x}$ on the interval from 0 to infinity

We now determine the critical values by differentiating and making the equation equal to 0

$f'(x)=2\pi*x- \frac{1680}{x^{2}} =\frac{2\pi x^{3}-1680}{x^{2} } =0$

This equation have 2 complex solutions and one real solution

$x=2\sqrt[3]{\frac{105}{\pi } }$

For x=0 and infinity the equation goes to infinity also so the radius of the base is equal to $x=2\sqrt[3]{\frac{105}{\pi } }$

And the height is equal to:

$y=\frac{840}{\pi (2\sqrt[3]{\frac{105}{\pi } })^{2} }$

$y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }$

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3 years ago

Carrie's friend lives two miles from her house. If it took her 18 % minutes to run to heltriend's

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Step-by-step explanation:

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3 years ago

What does that equation equal??

sattari [20]

Answer:

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Step-by-step explanation:

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4 years ago

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4 years ago

Read 2 more answers

A particular dam contains approximately 1,900,000,000,000 cubic feet of water. for a week long spike flood, the dam released at

Fantom [35]

Answer:

a) How much water was released during the flood?

14878080000 cubic feet or 14,878,080,000ft³

b) What percentage of the dam was released during the flood?

0.78%

Step-by-step explanation:

a) How much water was released during the flood?

The first step would be to find out how many seconds are in a week

60 seconds = 1 minute

60 minutes = 1 hour

24 hours = 1 day

7 days = 1 week

Hence, the number of seconds in a week =

1 week × (7 days/1 week)× (24 hours/1 day )×( 60 minutes/1 hour) ×( 60 seconds/1 minute)

= 604800 seconds

Therefore, the quantity of water released per week =

604800 seconds × 24,600 cubic feet per second

= 14,878,080,000 cubic feet or 14,878,080,000ft³

b) What percentage of the dam was released during the flood?

This is calculated as quantity released during the week ÷ Quantity of water in the dam × 100%

Quantity of water released during the flood in a week = 14,878,080,000 cubic feet

Quantity of water in the dam= 1,900,000,000,000 cubic feet of water

Percentage of the dam released during the flood =

14,878,080,000 cubic feet ÷ 1,900,000,000,000 × 100

= 0.7830568421%

Approximately = 0.78%

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3 years ago