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Talja [164]
3 years ago
6

At the movie theater child admission is 6.00 and adult admission is 9.90. On Sunday 118 tickets were sold for a total sales of 9

10.80 how many child tickets were sold that day
Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

19

Step-by-step explanation:

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N is an integer.<br>Write the values of n such that -15 &lt; 3 &lt; 6​
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

n could be : -14, -13, -12... -1, 0 , 1, 2, 3 ,4,5

3 0
3 years ago
A movie theater decreased the size of its popcorn bags by 20%. If the old bags held 15 cups of popcorn, how much do the new bags
vovikov84 [41]

Answer:

<em>Your answer will be </em>12<em> cups of popcorn.</em>

Step-by-step explanation:

To find out how much the new bags hold, you need to find out the discount.

\frac{20}{100 } = .2

15 * .2 = 3

<em>We know that the discount is </em>3<em>.</em>

<em>To figure out how much the new bags hold, subtract by the old bags.</em>

15 - 3 = 12

<em>The new bags hold 12 cups of popcorn. </em>

7 0
3 years ago
The difference between of two numbers is 9. If the large number is one more than twice the smaller number, find the larger numbe
sleet_krkn [62]

The larger number is 17

<em><u>Solution:</u></em>

Let "x" be the larger number

Let "y" be the smaller number

<em><u>The difference between of two numbers is 9</u></em>

Therefore,

larger number - smaller number = 9

x - y = 9 -------- eqn 1

<em><u>The large number is one more than twice the smaller number</u></em>

Larger number = 1 + 2(smaller number)

x = 1 + 2y ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

1 + 2y - y = 9

1 + y = 9

y = 9 - 1

y = 8

<em><u>Substitute y = 8 in eqn 1</u></em>

x - 8 = 9

x = 8 + 9

x = 17

Thus the larger number is 17

6 0
3 years ago
Please help and explain
Sonja [21]

Find out how much over the 10 years whatever it says and then use that to explain if it's worth is

3 0
3 years ago
A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (&gt; r) from th
jeyben [28]

Consider a circle with radius r centered at some point (R+r,0) on the x-axis. This circle has equation

(x-(R+r))^2+y^2=r^2

Revolve the region bounded by this circle across the y-axis to get a torus. Using the shell method, the volume of the resulting torus is

\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx

where 2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}.

So the volume is

\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx

Substitute

x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt

and the integral becomes

\displaystyle4\pi r^2\int_{-\pi/2}^{\pi/2}(R+r+r\sin t)\cos^2t\,\mathrm dt

Notice that \sin t\cos^2t is an odd function, so the integral over \left[-\frac\pi2,\frac\pi2\right] is 0. This leaves us with

\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt

Write

\cos^2t=\dfrac{1+\cos(2t)}2

so the volume is

\displaystyle2\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}(1+\cos(2t))\,\mathrm dt=\boxed{2\pi^2r^2(R+r)}

6 0
3 years ago
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