the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Let's see if that's really true! :)
170=x(17)
170=17x
17x=170
17x / 17=170 / 17
x=10
So the answer to your question is false.
170 is actually 10/1 OR 10 of 17.
Answer:
20 feet
Step-by-step explanation:
1st piece = x
2nd piece = 2x
3rd piece = 6x
x+2x+6x=180
9x=180
x=20
so the first piece is 20 feet, the second is 40, and the third is 120.
Answer:
56.924
Step-by-step explanation:
But there is no problem here
