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dlinn [17]
3 years ago
7

Write the slope-intercept form of the equation of the line described.

Mathematics
2 answers:
Romashka [77]3 years ago
6 0

Answer:

<h3>(4-4 = 0) - (4x5 =20) xDDddd</h3>
Sholpan [36]3 years ago
5 0

Answer:

y =  \frac{1}{4} x - 3

Step-by-step explanation:

<u>Slope-intercept form:</u>

y= mx +c, where m is the gradient and c is the y-intercept.

The product of the gradients of perpendicular lines is -1.

-4m= -1

m= -1 ÷(-4)

m= ¼

Substitute m= ¼ into the equation:

y= ¼x +c

To find the value of c, substitute a pair of coordinates.

y= ¼x +c

When x= -4, y= -4,

-4= ¼( -4) +c

-4= -1 +c

c= -4 +1

c= -3

Thus, the equation of the line is y= ¼x -3.

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In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
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Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

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Step-by-step explanation:

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