Write the slope-intercept form of the equation of the line described.
2 answers:
Answer:
Step-by-step explanation:
<u>Slope-intercept form:</u>
y= mx +c, where m is the gradient and c is the y-intercept.
The product of the gradients of perpendicular lines is -1.
-4m= -1
m= -1 ÷(-4)
m= ¼
Substitute m= ¼ into the equation:
y= ¼x +c
To find the value of c, substitute a pair of coordinates.
y= ¼x +c
When x= -4, y= -4,
-4= ¼( -4) +c
-4= -1 +c
c= -4 +1
c= -3
Thus, the equation of the line is y= ¼x -3.
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The answer is
G = [m1(veca1a2) + m2 (veca3a4) + m3veca5a6)] / (m1 + m2 + m3)
G= m1x5 + m2 x 4sqrt (2) + m3x 3sqrt (2) / 16 = 35 +4 x 3.7x sqrt (2) + 5.3 x3 4sqrt (2) / 16 =35 + 36<span> sqrt (2) / 16
G = 53.09
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</span>
G = [m1(veca1a2) + m2 (veca3a4) + m3veca5a6)] / (m1 + m2 + m3)
G= m1x5 + m2 x 4sqrt (2) + m3x 3sqrt (2) / 16 = 35 +4 x 3.7x sqrt (2) + 5.3 x3 4sqrt (2) / 16 =35 + 36<span> sqrt (2) / 16
G = 53.09
LOOK AT THE IMAGE
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